4(2z=3)12

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Solution for 4(2z=3)12 equation: 



4(2z=3)12

We move all terms to the left:

4(2z-(3)12)=0

We multiply parentheses

8z-1248=0

We move all terms containing z to the left, all other terms to the right

8z=1248

z=1248/8

z=156

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