(3x+2x-4x)=(5x-2x+3x)

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Solution for (3x+2x-4x)=(5x-2x+3x) equation: 



(3x+2x-4x)=(5x-2x+3x)

We move all terms to the left:

(3x+2x-4x)-((5x-2x+3x))=0

We add all the numbers together, and all the variables

(+x)-((+6x))=0

We get rid of parentheses

x-((+6x))=0



We calculate terms in parentheses: -((+6x)), so:

(+6x)

We get rid of parentheses

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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