4(2z-4)=32

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Solution for 4(2z-4)=32 equation: 



4(2z-4)=32

We move all terms to the left:

4(2z-4)-(32)=0

We multiply parentheses

8z-16-32=0

We add all the numbers together, and all the variables

8z-48=0

We move all terms containing z to the left, all other terms to the right

8z=48

z=48/8

z=6

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