-5(-3u+2)-3u=2(u-3)-2

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Solution for -5(-3u+2)-3u=2(u-3)-2 equation: 



-5(-3u+2)-3u=2(u-3)-2

We move all terms to the left:

-5(-3u+2)-3u-(2(u-3)-2)=0

We add all the numbers together, and all the variables

-3u-5(-3u+2)-(2(u-3)-2)=0

We multiply parentheses

-3u+15u-(2(u-3)-2)-10=0



We calculate terms in parentheses: -(2(u-3)-2), so:

2(u-3)-2

We multiply parentheses

2u-6-2

We add all the numbers together, and all the variables

2u-8

Back to the equation:

-(2u-8)



We add all the numbers together, and all the variables

12u-(2u-8)-10=0

We get rid of parentheses

12u-2u+8-10=0

We add all the numbers together, and all the variables

10u-2=0

We move all terms containing u to the left, all other terms to the right

10u=2

u=2/10

u=1/5

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