4(2z-3)=2(z+3)-3(2+1)

Solution for 4(2z-3)=2(z+3)-3(2+1) equation:

4(2z-3)=2(z+3)-3(2+1)

We move all terms to the left:

4(2z-3)-(2(z+3)-3(2+1))=0

We add all the numbers together, and all the variables

4(2z-3)-(2(z+3)-33)=0

We multiply parentheses

8z-(2(z+3)-33)-12=0


We calculate terms in parentheses: -(2(z+3)-33), so:

2(z+3)-33

We multiply parentheses

2z+6-33

We add all the numbers together, and all the variables

2z-27

Back to the equation:

-(2z-27)


We get rid of parentheses

8z-2z+27-12=0

We add all the numbers together, and all the variables

6z+15=0

We move all terms containing z to the left, all other terms to the right

6z=-15

z=-15/6

z=-2+1/2