6/1-z=9/2(1+z)

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Solution for 6/1-z=9/2(1+z) equation: 



6/1-z=9/2(1+z)

We move all terms to the left:

6/1-z-(9/2(1+z))=0



Domain of the equation: 2(1+z))!=0

z∈R



We add all the numbers together, and all the variables

-z-(9/2(z+1))+6/1=0

We add all the numbers together, and all the variables

-1z-(9/2(z+1))=0

We multiply all the terms by the denominator


-1z*2(z+1))-(9=0

Wy multiply elements

-2z^2(z=0

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