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4(2z-2)+1=7(z+4)
We move all terms to the left:
4(2z-2)+1-(7(z+4))=0
We multiply parentheses
8z-(7(z+4))-8+1=0
We calculate terms in parentheses: -(7(z+4)), so:We add all the numbers together, and all the variables
7(z+4)
We multiply parentheses
7z+28
Back to the equation:
-(7z+28)
8z-(7z+28)-7=0
We get rid of parentheses
8z-7z-28-7=0
We add all the numbers together, and all the variables
z-35=0
We move all terms containing z to the left, all other terms to the right
z=35
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