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1/3b-(b+1/5)=1/15(b+1)
We move all terms to the left:
1/3b-(b+1/5)-(1/15(b+1))=0
Domain of the equation: 3b!=0
b!=0/3
b!=0
b∈R
Domain of the equation: 15(b+1))!=0We add all the numbers together, and all the variables
b∈R
1/3b-(+b+1/5)-(1/15(b+1))=0
We get rid of parentheses
1/3b-b-(1/15(b+1))-1/5=0
We calculate fractions
(75bb/(225b^2b+(-(1*3b*5)/(225b^2b+(-45b^2)/(225b^2b-b=0
We can not solve this equation
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