4(2z+1)=z-3(4z-5)

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Solution for 4(2z+1)=z-3(4z-5) equation: 



4(2z+1)=z-3(4z-5)

We move all terms to the left:

4(2z+1)-(z-3(4z-5))=0

We multiply parentheses

8z-(z-3(4z-5))+4=0



We calculate terms in parentheses: -(z-3(4z-5)), so:

z-3(4z-5)

We multiply parentheses

z-12z+15

We add all the numbers together, and all the variables

-11z+15

Back to the equation:

-(-11z+15)



We get rid of parentheses

8z+11z-15+4=0

We add all the numbers together, and all the variables

19z-11=0

We move all terms containing z to the left, all other terms to the right

19z=11

z=11/19

z=11/19

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