t+48+2t+t+27+t+32+2t+102=120

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Solution for t+48+2t+t+27+t+32+2t+102=120 equation: 



t+48+2t+t+27+t+32+2t+102=120

We move all terms to the left:

t+48+2t+t+27+t+32+2t+102-(120)=0

We add all the numbers together, and all the variables

7t+89=0

We move all terms containing t to the left, all other terms to the right

7t=-89

t=-89/7

t=-12+5/7

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