4(2y-3)-7y=5(y-4)

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Solution for 4(2y-3)-7y=5(y-4) equation: 



4(2y-3)-7y=5(y-4)

We move all terms to the left:

4(2y-3)-7y-(5(y-4))=0

We add all the numbers together, and all the variables

-7y+4(2y-3)-(5(y-4))=0

We multiply parentheses

-7y+8y-(5(y-4))-12=0



We calculate terms in parentheses: -(5(y-4)), so:

5(y-4)

We multiply parentheses

5y-20

Back to the equation:

-(5y-20)



We add all the numbers together, and all the variables

y-(5y-20)-12=0

We get rid of parentheses

y-5y+20-12=0

We add all the numbers together, and all the variables

-4y+8=0

We move all terms containing y to the left, all other terms to the right

-4y=-8

y=-8/-4

y=+2

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