4(2y-3)-7=5(y-4)

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Solution for 4(2y-3)-7=5(y-4) equation: 



4(2y-3)-7=5(y-4)

We move all terms to the left:

4(2y-3)-7-(5(y-4))=0

We multiply parentheses

8y-(5(y-4))-12-7=0



We calculate terms in parentheses: -(5(y-4)), so:

5(y-4)

We multiply parentheses

5y-20

Back to the equation:

-(5y-20)



We add all the numbers together, and all the variables

8y-(5y-20)-19=0

We get rid of parentheses

8y-5y+20-19=0

We add all the numbers together, and all the variables

3y+1=0

We move all terms containing y to the left, all other terms to the right

3y=-1

y=-1/3

y=-1/3

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