4(2y-2)=3(3y+4)=

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Solution for 4(2y-2)=3(3y+4)= equation: 



4(2y-2)=3(3y+4)=

We move all terms to the left:

4(2y-2)-(3(3y+4))=0

We multiply parentheses

8y-(3(3y+4))-8=0



We calculate terms in parentheses: -(3(3y+4)), so:

3(3y+4)

We multiply parentheses

9y+12

Back to the equation:

-(9y+12)



We get rid of parentheses

8y-9y-12-8=0

We add all the numbers together, and all the variables

-1y-20=0

We move all terms containing y to the left, all other terms to the right

-y=20

y=20/-1

y=-20

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