3(2y+7)+7y=34

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Solution for 3(2y+7)+7y=34 equation: 



3(2y+7)+7y=34

We move all terms to the left:

3(2y+7)+7y-(34)=0

We add all the numbers together, and all the variables

7y+3(2y+7)-34=0

We multiply parentheses

7y+6y+21-34=0

We add all the numbers together, and all the variables

13y-13=0

We move all terms containing y to the left, all other terms to the right

13y=13

y=13/13

y=1

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