4(2y+3)=2(12-y)

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Solution for 4(2y+3)=2(12-y) equation: 



4(2y+3)=2(12-y)

We move all terms to the left:

4(2y+3)-(2(12-y))=0

We add all the numbers together, and all the variables

4(2y+3)-(2(-1y+12))=0

We multiply parentheses

8y-(2(-1y+12))+12=0



We calculate terms in parentheses: -(2(-1y+12)), so:

2(-1y+12)

We multiply parentheses

-2y+24

Back to the equation:

-(-2y+24)



We get rid of parentheses

8y+2y-24+12=0

We add all the numbers together, and all the variables

10y-12=0

We move all terms containing y to the left, all other terms to the right

10y=12

y=12/10

y=1+1/5

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