4(2y+-8)=-40

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Solution for 4(2y+-8)=-40 equation:



4(2y+-8)=-40
We move all terms to the left:
4(2y+-8)-(-40)=0
We add all the numbers together, and all the variables
4(2y-8)-(-40)=0
We add all the numbers together, and all the variables
4(2y-8)+40=0
We multiply parentheses
8y-32+40=0
We add all the numbers together, and all the variables
8y+8=0
We move all terms containing y to the left, all other terms to the right
8y=-8
y=-8/8
y=-1

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