2m-4(m+1)=4(m+3)

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Solution for 2m-4(m+1)=4(m+3) equation:



2m-4(m+1)=4(m+3)
We move all terms to the left:
2m-4(m+1)-(4(m+3))=0
We multiply parentheses
2m-4m-(4(m+3))-4=0
We calculate terms in parentheses: -(4(m+3)), so:
4(m+3)
We multiply parentheses
4m+12
Back to the equation:
-(4m+12)
We add all the numbers together, and all the variables
-2m-(4m+12)-4=0
We get rid of parentheses
-2m-4m-12-4=0
We add all the numbers together, and all the variables
-6m-16=0
We move all terms containing m to the left, all other terms to the right
-6m=16
m=16/-6
m=-2+2/3

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