4(2x-8)=6(x-18)+12x

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Solution for 4(2x-8)=6(x-18)+12x equation: 



4(2x-8)=6(x-18)+12x

We move all terms to the left:

4(2x-8)-(6(x-18)+12x)=0

We multiply parentheses

8x-(6(x-18)+12x)-32=0



We calculate terms in parentheses: -(6(x-18)+12x), so:

6(x-18)+12x

We add all the numbers together, and all the variables

12x+6(x-18)

We multiply parentheses

12x+6x-108

We add all the numbers together, and all the variables

18x-108

Back to the equation:

-(18x-108)



We get rid of parentheses

8x-18x+108-32=0

We add all the numbers together, and all the variables

-10x+76=0

We move all terms containing x to the left, all other terms to the right

-10x=-76

x=-76/-10

x=7+3/5

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