3(x-4)=2(6+2x)

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Solution for 3(x-4)=2(6+2x) equation: 



3(x-4)=2(6+2x)

We move all terms to the left:

3(x-4)-(2(6+2x))=0

We add all the numbers together, and all the variables

3(x-4)-(2(2x+6))=0

We multiply parentheses

3x-(2(2x+6))-12=0



We calculate terms in parentheses: -(2(2x+6)), so:

2(2x+6)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

3x-4x-12-12=0

We add all the numbers together, and all the variables

-1x-24=0

We move all terms containing x to the left, all other terms to the right

-x=24

x=24/-1

x=-24

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