4(2x-7)-3=4(x-3)+1

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Solution for 4(2x-7)-3=4(x-3)+1 equation: 



4(2x-7)-3=4(x-3)+1

We move all terms to the left:

4(2x-7)-3-(4(x-3)+1)=0

We multiply parentheses

8x-(4(x-3)+1)-28-3=0



We calculate terms in parentheses: -(4(x-3)+1), so:

4(x-3)+1

We multiply parentheses

4x-12+1

We add all the numbers together, and all the variables

4x-11

Back to the equation:

-(4x-11)



We add all the numbers together, and all the variables

8x-(4x-11)-31=0

We get rid of parentheses

8x-4x+11-31=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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