(2x-5/4x+12)+9/x+3=0

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Solution for (2x-5/4x+12)+9/x+3=0 equation: 



(2x-5/4x+12)+9/x+3=0



Domain of the equation: 4x+12)!=0

x∈R





Domain of the equation: x!=0

x∈R



We get rid of parentheses

2x-5/4x+9/x+12+3=0

We calculate fractions


2x+(-5x)/4x^2+36x/4x^2+12+3=0

We add all the numbers together, and all the variables

2x+(-5x)/4x^2+36x/4x^2+15=0

We multiply all the terms by the denominator


2x*4x^2+(-5x)+36x+15*4x^2=0

We add all the numbers together, and all the variables

36x+2x*4x^2+(-5x)+15*4x^2=0

Wy multiply elements

8x^3+60x^2+36x+(-5x)=0

We get rid of parentheses

8x^3+60x^2+36x-5x=0

We do not support expression: x^3

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