4(2x-5)-(7-3x)=4(x+3)

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Solution for 4(2x-5)-(7-3x)=4(x+3) equation: 



4(2x-5)-(7-3x)=4(x+3)

We move all terms to the left:

4(2x-5)-(7-3x)-(4(x+3))=0

We add all the numbers together, and all the variables

4(2x-5)-(-3x+7)-(4(x+3))=0

We multiply parentheses

8x-(-3x+7)-(4(x+3))-20=0

We get rid of parentheses

8x+3x-(4(x+3))-7-20=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

11x-(4x+12)-27=0

We get rid of parentheses

11x-4x-12-27=0

We add all the numbers together, and all the variables

7x-39=0

We move all terms containing x to the left, all other terms to the right

7x=39

x=39/7

x=5+4/7

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