A=5H(b+B)b

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Solution for A=5H(b+B)b equation: 



=5(A+)A

We move all terms to the left:

-(5(A+)A)=0

We add all the numbers together, and all the variables

-(5(+A)A)=0



We calculate terms in parentheses: -(5(+A)A), so:

5(+A)A

We multiply parentheses

5A^2

Back to the equation:

-(5A^2)



a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{-10}=0$

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