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4(2x-5)+16=x-32
We move all terms to the left:
4(2x-5)+16-(x-32)=0
We multiply parentheses
8x-(x-32)-20+16=0
We get rid of parentheses
8x-x+32-20+16=0
We add all the numbers together, and all the variables
7x+28=0
We move all terms containing x to the left, all other terms to the right
7x=-28
x=-28/7
x=-4
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