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X2+21X+80=0
We add all the numbers together, and all the variables
X^2+21X+80=0
a = 1; b = 21; c = +80;
Δ = b2-4ac
Δ = 212-4·1·80
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-11}{2*1}=\frac{-32}{2} =-16 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+11}{2*1}=\frac{-10}{2} =-5 $
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