4(2x-5)+12=64

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Solution for 4(2x-5)+12=64 equation: 



4(2x-5)+12=64

We move all terms to the left:

4(2x-5)+12-(64)=0

We add all the numbers together, and all the variables

4(2x-5)-52=0

We multiply parentheses

8x-20-52=0

We add all the numbers together, and all the variables

8x-72=0

We move all terms containing x to the left, all other terms to the right

8x=72

x=72/8

x=9

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