7(2x-1)+3x-10(x+3)=-5x+2(x-11)+6x

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Solution for 7(2x-1)+3x-10(x+3)=-5x+2(x-11)+6x equation: 



7(2x-1)+3x-10(x+3)=-5x+2(x-11)+6x

We move all terms to the left:

7(2x-1)+3x-10(x+3)-(-5x+2(x-11)+6x)=0

We add all the numbers together, and all the variables

3x+7(2x-1)-10(x+3)-(-5x+2(x-11)+6x)=0

We multiply parentheses

3x+14x-10x-(-5x+2(x-11)+6x)-7-30=0



We calculate terms in parentheses: -(-5x+2(x-11)+6x), so:

-5x+2(x-11)+6x

We add all the numbers together, and all the variables

x+2(x-11)

We multiply parentheses

x+2x-22

We add all the numbers together, and all the variables

3x-22

Back to the equation:

-(3x-22)



We add all the numbers together, and all the variables

7x-(3x-22)-37=0

We get rid of parentheses

7x-3x+22-37=0

We add all the numbers together, and all the variables

4x-15=0

We move all terms containing x to the left, all other terms to the right

4x=15

x=15/4

x=3+3/4

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