4(2x-4)-7(2x-4)=-48

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Solution for 4(2x-4)-7(2x-4)=-48 equation: 



4(2x-4)-7(2x-4)=-48

We move all terms to the left:

4(2x-4)-7(2x-4)-(-48)=0

We add all the numbers together, and all the variables

4(2x-4)-7(2x-4)+48=0

We multiply parentheses

8x-14x-16+28+48=0

We add all the numbers together, and all the variables

-6x+60=0

We move all terms containing x to the left, all other terms to the right

-6x=-60

x=-60/-6

x=+10

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