2(y-7)-3=-5(-5y+1)-9y

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Solution for 2(y-7)-3=-5(-5y+1)-9y equation: 



2(y-7)-3=-5(-5y+1)-9y

We move all terms to the left:

2(y-7)-3-(-5(-5y+1)-9y)=0

We multiply parentheses

2y-(-5(-5y+1)-9y)-14-3=0



We calculate terms in parentheses: -(-5(-5y+1)-9y), so:

-5(-5y+1)-9y

We add all the numbers together, and all the variables

-9y-5(-5y+1)

We multiply parentheses

-9y+25y-5

We add all the numbers together, and all the variables

16y-5

Back to the equation:

-(16y-5)



We add all the numbers together, and all the variables

2y-(16y-5)-17=0

We get rid of parentheses

2y-16y+5-17=0

We add all the numbers together, and all the variables

-14y-12=0

We move all terms containing y to the left, all other terms to the right

-14y=12

y=12/-14

y=-6/7

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