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4(2x-3)-3(5x-3)=7x-(5x-4)
We move all terms to the left:
4(2x-3)-3(5x-3)-(7x-(5x-4))=0
We multiply parentheses
8x-15x-(7x-(5x-4))-12+9=0
We calculate terms in parentheses: -(7x-(5x-4)), so:We add all the numbers together, and all the variables
7x-(5x-4)
We get rid of parentheses
7x-5x+4
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
-7x-(2x+4)-3=0
We get rid of parentheses
-7x-2x-4-3=0
We add all the numbers together, and all the variables
-9x-7=0
We move all terms containing x to the left, all other terms to the right
-9x=7
x=7/-9
x=-7/9
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