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(5x-16)(3x+28)=0
We multiply parentheses ..
(+15x^2+140x-48x-448)=0
We get rid of parentheses
15x^2+140x-48x-448=0
We add all the numbers together, and all the variables
15x^2+92x-448=0
a = 15; b = 92; c = -448;
Δ = b2-4ac
Δ = 922-4·15·(-448)
Δ = 35344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{35344}=188$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-188}{2*15}=\frac{-280}{30} =-9+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+188}{2*15}=\frac{96}{30} =3+1/5 $
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