5y+2(y-8)=4(y-2)-2

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Solution for 5y+2(y-8)=4(y-2)-2 equation: 



5y+2(y-8)=4(y-2)-2

We move all terms to the left:

5y+2(y-8)-(4(y-2)-2)=0

We multiply parentheses

5y+2y-(4(y-2)-2)-16=0



We calculate terms in parentheses: -(4(y-2)-2), so:

4(y-2)-2

We multiply parentheses

4y-8-2

We add all the numbers together, and all the variables

4y-10

Back to the equation:

-(4y-10)



We add all the numbers together, and all the variables

7y-(4y-10)-16=0

We get rid of parentheses

7y-4y+10-16=0

We add all the numbers together, and all the variables

3y-6=0

We move all terms containing y to the left, all other terms to the right

3y=6

y=6/3

y=2

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