4(2x-1)-2(3x-5)=3(x-2)

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Solution for 4(2x-1)-2(3x-5)=3(x-2) equation:



4(2x-1)-2(3x-5)=3(x-2)
We move all terms to the left:
4(2x-1)-2(3x-5)-(3(x-2))=0
We multiply parentheses
8x-6x-(3(x-2))-4+10=0
We calculate terms in parentheses: -(3(x-2)), so:
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
We add all the numbers together, and all the variables
2x-(3x-6)+6=0
We get rid of parentheses
2x-3x+6+6=0
We add all the numbers together, and all the variables
-1x+12=0
We move all terms containing x to the left, all other terms to the right
-x=-12
x=-12/-1
x=+12

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