25=3(7k-8)+7(k-5)

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Solution for 25=3(7k-8)+7(k-5) equation: 



25=3(7k-8)+7(k-5)

We move all terms to the left:

25-(3(7k-8)+7(k-5))=0



We calculate terms in parentheses: -(3(7k-8)+7(k-5)), so:

3(7k-8)+7(k-5)

We multiply parentheses

21k+7k-24-35

We add all the numbers together, and all the variables

28k-59

Back to the equation:

-(28k-59)



We get rid of parentheses

-28k+59+25=0

We add all the numbers together, and all the variables

-28k+84=0

We move all terms containing k to the left, all other terms to the right

-28k=-84

k=-84/-28

k=+3

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