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4(2x-1)-2(2x-5)=5(x+1)+3
We move all terms to the left:
4(2x-1)-2(2x-5)-(5(x+1)+3)=0
We multiply parentheses
8x-4x-(5(x+1)+3)-4+10=0
We calculate terms in parentheses: -(5(x+1)+3), so:We add all the numbers together, and all the variables
5(x+1)+3
We multiply parentheses
5x+5+3
We add all the numbers together, and all the variables
5x+8
Back to the equation:
-(5x+8)
4x-(5x+8)+6=0
We get rid of parentheses
4x-5x-8+6=0
We add all the numbers together, and all the variables
-1x-2=0
We move all terms containing x to the left, all other terms to the right
-x=2
x=2/-1
x=-2
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