4(2x+7)3x=48

Solution for 4(2x+7)3x=48 equation:

4(2x+7)3x=48

We move all terms to the left:

4(2x+7)3x-(48)=0

We multiply parentheses

24x^2+84x-48=0

a = 24; b = 84; c = -48;
Δ = b2-4ac
Δ = 842-4·24·(-48)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-108}{2*24}=\frac{-192}{48}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+108}{2*24}=\frac{24}{48}
=1/2
$