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4(2x+5)=7(x-12)
We move all terms to the left:
4(2x+5)-(7(x-12))=0
We multiply parentheses
8x-(7(x-12))+20=0
We calculate terms in parentheses: -(7(x-12)), so:We get rid of parentheses
7(x-12)
We multiply parentheses
7x-84
Back to the equation:
-(7x-84)
8x-7x+84+20=0
We add all the numbers together, and all the variables
x+104=0
We move all terms containing x to the left, all other terms to the right
x=-104
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