-3(x+4)+5(3-2x)=2(x-1)-4(3-2x)

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Solution for -3(x+4)+5(3-2x)=2(x-1)-4(3-2x) equation: 



-3(x+4)+5(3-2x)=2(x-1)-4(3-2x)

We move all terms to the left:

-3(x+4)+5(3-2x)-(2(x-1)-4(3-2x))=0

We add all the numbers together, and all the variables

-3(x+4)+5(-2x+3)-(2(x-1)-4(-2x+3))=0

We multiply parentheses

-3x-10x-(2(x-1)-4(-2x+3))-12+15=0



We calculate terms in parentheses: -(2(x-1)-4(-2x+3)), so:

2(x-1)-4(-2x+3)

We multiply parentheses

2x+8x-2-12

We add all the numbers together, and all the variables

10x-14

Back to the equation:

-(10x-14)



We add all the numbers together, and all the variables

-13x-(10x-14)+3=0

We get rid of parentheses

-13x-10x+14+3=0

We add all the numbers together, and all the variables

-23x+17=0

We move all terms containing x to the left, all other terms to the right

-23x=-17

x=-17/-23

x=17/23

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