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4(2x+3)=2(3x+2)+(2x+1)
We move all terms to the left:
4(2x+3)-(2(3x+2)+(2x+1))=0
We multiply parentheses
8x-(2(3x+2)+(2x+1))+12=0
We calculate terms in parentheses: -(2(3x+2)+(2x+1)), so:We get rid of parentheses
2(3x+2)+(2x+1)
We multiply parentheses
6x+(2x+1)+4
We get rid of parentheses
6x+2x+1+4
We add all the numbers together, and all the variables
8x+5
Back to the equation:
-(8x+5)
8x-8x-5+12=0
We add all the numbers together, and all the variables
7!=0
There is no solution for this equation
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