4(2x+2)=6x+28

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Solution for 4(2x+2)=6x+28 equation:



4(2x+2)=6x+28
We move all terms to the left:
4(2x+2)-(6x+28)=0
We multiply parentheses
8x-(6x+28)+8=0
We get rid of parentheses
8x-6x-28+8=0
We add all the numbers together, and all the variables
2x-20=0
We move all terms containing x to the left, all other terms to the right
2x=20
x=20/2
x=10

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