3x2+23x=-20

Solution for 3x2+23x=-20 equation:

3x^2+23x=-20

We move all terms to the left:

3x^2+23x-(-20)=0

We add all the numbers together, and all the variables

3x^2+23x+20=0

a = 3; b = 23; c = +20;
Δ = b2-4ac
Δ = 232-4·3·20
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-17}{2*3}=\frac{-40}{6}
=-6+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+17}{2*3}=\frac{-6}{6}
=-1
$