4(2x+2)+1=8(x+1)

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Solution for 4(2x+2)+1=8(x+1) equation: 



4(2x+2)+1=8(x+1)

We move all terms to the left:

4(2x+2)+1-(8(x+1))=0

We multiply parentheses

8x-(8(x+1))+8+1=0



We calculate terms in parentheses: -(8(x+1)), so:

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We add all the numbers together, and all the variables

8x-(8x+8)+9=0

We get rid of parentheses

8x-8x-8+9=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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