6(15-x)=40-x

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Solution for 6(15-x)=40-x equation: 



6(15-x)=40-x

We move all terms to the left:

6(15-x)-(40-x)=0

We add all the numbers together, and all the variables

6(-1x+15)-(-1x+40)=0

We multiply parentheses

-6x-(-1x+40)+90=0

We get rid of parentheses

-6x+1x-40+90=0

We add all the numbers together, and all the variables

-5x+50=0

We move all terms containing x to the left, all other terms to the right

-5x=-50

x=-50/-5

x=+10

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