4(2x+1)=7-(3x-2)

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Solution for 4(2x+1)=7-(3x-2) equation: 



4(2x+1)=7-(3x-2)

We move all terms to the left:

4(2x+1)-(7-(3x-2))=0

We multiply parentheses

8x-(7-(3x-2))+4=0



We calculate terms in parentheses: -(7-(3x-2)), so:

7-(3x-2)

determiningTheFunctionDomain
-(3x-2)+7

We get rid of parentheses

-3x+2+7

We add all the numbers together, and all the variables

-3x+9

Back to the equation:

-(-3x+9)



We get rid of parentheses

8x+3x-9+4=0

We add all the numbers together, and all the variables

11x-5=0

We move all terms containing x to the left, all other terms to the right

11x=5

x=5/11

x=5/11

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