2/3(x+3)-7=x+4

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Solution for 2/3(x+3)-7=x+4 equation: 



2/3(x+3)-7=x+4

We move all terms to the left:

2/3(x+3)-7-(x+4)=0



Domain of the equation: 3(x+3)!=0

x∈R



We get rid of parentheses

2/3(x+3)-x-4-7=0

We multiply all the terms by the denominator


-x*3(x+3)-4*3(x+3)-7*3(x+3)+2=0

Wy multiply elements

-3x^2(x-12x(x-21x(x+2=0

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