4(2x+1)=27+3(2x+1)

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Solution for 4(2x+1)=27+3(2x+1) equation: 



4(2x+1)=27+3(2x+1)

We move all terms to the left:

4(2x+1)-(27+3(2x+1))=0

We multiply parentheses

8x-(27+3(2x+1))+4=0



We calculate terms in parentheses: -(27+3(2x+1)), so:

27+3(2x+1)

determiningTheFunctionDomain
3(2x+1)+27

We multiply parentheses

6x+3+27

We add all the numbers together, and all the variables

6x+30

Back to the equation:

-(6x+30)



We get rid of parentheses

8x-6x-30+4=0

We add all the numbers together, and all the variables

2x-26=0

We move all terms containing x to the left, all other terms to the right

2x=26

x=26/2

x=13

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