-16t*t+32t+4=0

Solution for -16t*t+32t+4=0 equation:

-16t*t+32t+4=0

We add all the numbers together, and all the variables

32t-16t*t+4=0

Wy multiply elements

-16t^2+32t+4=0

a = -16; b = 32; c = +4;
Δ = b2-4ac
Δ = 322-4·(-16)·4
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16\sqrt{5}}{2*-16}=\frac{-32-16\sqrt{5}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16\sqrt{5}}{2*-16}=\frac{-32+16\sqrt{5}}{-32}
$