10(r-1)+1=6(r-12)-5r

Solution for 10(r-1)+1=6(r-12)-5r equation:

10(r-1)+1=6(r-12)-5r

We move all terms to the left:

10(r-1)+1-(6(r-12)-5r)=0

We multiply parentheses

10r-(6(r-12)-5r)-10+1=0


We calculate terms in parentheses: -(6(r-12)-5r), so:

6(r-12)-5r

We add all the numbers together, and all the variables

-5r+6(r-12)

We multiply parentheses

-5r+6r-72

We add all the numbers together, and all the variables

r-72

Back to the equation:

-(r-72)


We add all the numbers together, and all the variables

10r-(r-72)-9=0

We get rid of parentheses

10r-r+72-9=0

We add all the numbers together, and all the variables

9r+63=0

We move all terms containing r to the left, all other terms to the right

9r=-63

r=-63/9

r=-7