4(2w-4)+20=4(2w-1)+8

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Solution for 4(2w-4)+20=4(2w-1)+8 equation: 



4(2w-4)+20=4(2w-1)+8

We move all terms to the left:

4(2w-4)+20-(4(2w-1)+8)=0

We multiply parentheses

8w-(4(2w-1)+8)-16+20=0



We calculate terms in parentheses: -(4(2w-1)+8), so:

4(2w-1)+8

We multiply parentheses

8w-4+8

We add all the numbers together, and all the variables

8w+4

Back to the equation:

-(8w+4)



We add all the numbers together, and all the variables

8w-(8w+4)+4=0

We get rid of parentheses

8w-8w-4+4=0

We add all the numbers together, and all the variables

=0

w=0/1

w=0

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