107-(7x+4)=7(x+4)+x

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Solution for 107-(7x+4)=7(x+4)+x equation: 



107-(7x+4)=7(x+4)+x

We move all terms to the left:

107-(7x+4)-(7(x+4)+x)=0

We get rid of parentheses

-7x-(7(x+4)+x)-4+107=0



We calculate terms in parentheses: -(7(x+4)+x), so:

7(x+4)+x

We add all the numbers together, and all the variables

x+7(x+4)

We multiply parentheses

x+7x+28

We add all the numbers together, and all the variables

8x+28

Back to the equation:

-(8x+28)



We add all the numbers together, and all the variables

-7x-(8x+28)+103=0

We get rid of parentheses

-7x-8x-28+103=0

We add all the numbers together, and all the variables

-15x+75=0

We move all terms containing x to the left, all other terms to the right

-15x=-75

x=-75/-15

x=+5

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